What is 1/24 (t-4)^4e^{-3(t-4)}u(t-4) ?

The solution to 1/24 (t-4)^4e^{-3(t-4)}u(t-4) is (e^{-3(t-4)}u(t-4)^5)/(24)

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simplify 1/24 (t-4)^4e^{-3(t-4)}u(t-4)

simplify

\frac{1}{24} (t - 4)^{4} e^{- 3 (t - 4)} u (t - 4)

\frac{e ^{- 3 (t - 4)} u ( t - 4 ) ^{5}}{24}

Solution steps

\frac{1}{24} (t - 4)^{4} e^{- 3 (t - 4)} u (t - 4)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(t - 4)^{4} (t - 4) = (t - 4)^{4 + 1}

= \frac{1}{24} e^{- 3 (t - 4)} u (t - 4)^{4 + 1}

Add the numbers:

4 + 1 = 5

= \frac{1}{24} e^{- 3 (t - 4)} u (t - 4)^{5}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= e^{- 3 (t - 4)} \frac{1 \cdot u ( t - 4 ) ^{5}}{24}

Multiply:

1 \cdot u = u

= e^{- 3 (t - 4)} \frac{u ( t - 4 ) ^{5}}{24}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{u ( t - 4 ) ^{5} e ^{- 3 (t - 4)}}{24}

e^{- (t - \frac{π}{4})}

0.0195 \cdot 228. 9^{0.77} \cdot 0.017 5^{- 0.385}

e^{- y} g

2 \cdot 2 \cdot π \cdot 1 5^{2}

e^{- x} \cdot x^{2} \cdot sin (x)

What is 1/24 (t-4)^4e^{-3(t-4)}u(t-4) ?
The solution to 1/24 (t-4)^4e^{-3(t-4)}u(t-4) is (e^{-3(t-4)}u(t-4)^5)/(24)