What are the solutions to the equation 4h^2+12h+1=0 ?

The solutions to the equation 4h^2+12h+1=0 are h=(-3+2sqrt(2))/2 ,h=-(3+2sqrt(2))/2

Find the zeros of 4h^2+12h+1=0

The zeros of 4h^2+12h+1=0 are h=(-3+2sqrt(2))/2 ,h=-(3+2sqrt(2))/2

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4 h^{2} + 12 h + 1 = 0

h = \frac{- 3 + 2 2}{2}, h = - \frac{3 + 2 2}{2}

Solution steps

4 h^{2} + 12 h + 1 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 1 = 82

h_{1, 2} = \frac{- 12 \pm 8 2}{2 \cdot 4}

Separate the solutions

h_{1} = \frac{- 12 + 8 2}{2 \cdot 4}, h_{2} = \frac{- 12 - 8 2}{2 \cdot 4}

h = \frac{- 12 + 8 2}{2 \cdot 4} : \frac{- 3 + 2 2}{2}

h = \frac{- 12 - 8 2}{2 \cdot 4} : - \frac{3 + 2 2}{2}

The solutions to the quadratic equation are:

h = \frac{- 3 + 2 2}{2}, h = - \frac{3 + 2 2}{2}

- 180 (1 - \frac{5}{50})

427 \cdot 26

\frac{3}{x} < 5

x^{2} - 1 x - 12

1 + \frac{0.05}{2}

What are the solutions to the equation 4h^2+12h+1=0 ?
The solutions to the equation 4h^2+12h+1=0 are h=(-3+2sqrt(2))/2 ,h=-(3+2sqrt(2))/2
Find the zeros of 4h^2+12h+1=0
The zeros of 4h^2+12h+1=0 are h=(-3+2sqrt(2))/2 ,h=-(3+2sqrt(2))/2