What is (1/(Qmax))*(e^{-x}) ?

The solution to (1/(Qmax))*(e^{-x}) is 1/(ae^xQmx)

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simplify (1/(Qmax))*(e^{-x})

simplify

(\frac{1}{Q ma x}) \cdot (e^{- x})

\frac{1}{a e ^{x} Q m x}

Solution steps

(\frac{1}{Q ma x}) (e^{- x})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{a Q m x} \cdot \frac{1}{e ^{x}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{Q ma x e ^{x}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{a e ^{x} Q m x}

12 \cdot e^{- \frac{25}{( 1 0 ^{6} \cdot 4 \cdot 1 0 ^{- 6} )}}

(1.6 \cdot 1 0^{- 19}) \cdot (4 \cdot 1 0^{- 17})

(234 \cdot 1 0^{6}) (79.2 \cdot 1 0^{- 6})

700 e^{- 0.24 \cdot 15}

(1 - x)^{2} \cdot e^{- x}

What is (1/(Qmax))*(e^{-x}) ?
The solution to (1/(Qmax))*(e^{-x}) is 1/(ae^xQmx)