What is \sqrt[5]{3^3}*(\sqrt[15]{3^2})^3 ?

The solution to \sqrt[5]{3^3}*(\sqrt[15]{3^2})^3 is 3

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simplify \sqrt[5]{3^3}*(\sqrt[15]{3^2})^3

simplify

3

Solution steps

= 3^{\frac{3}{5}} (3^{\frac{2}{15}})^{3}

(3^{\frac{2}{15}})^{3} = 3^{\frac{2}{5}}

= 3^{\frac{3}{5}} \cdot 3^{\frac{2}{5}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

3^{\frac{3}{5}} \cdot 3^{\frac{2}{5}} = 3^{\frac{3}{5} + \frac{2}{5}}

= 3^{\frac{3}{5} + \frac{2}{5}}

Join

\frac{3}{5} + \frac{2}{5} : 1

= 3^{1}

Apply rule

a^{1} = a

= 3

7 \cdot (14.8 \cdot 1 0^{- 3})

e^{x} \cdot 3 e^{- x}

[b e g ina rr a ycc c^{1}] 11200130001 e n d a rr a y

(6 g) (6 c m^{2})

What is \sqrt[5]{3^3}*(\sqrt[15]{3^2})^3 ?
The solution to \sqrt[5]{3^3}*(\sqrt[15]{3^2})^3 is 3