What are the solutions to the equation t^2-6t-40=0 ?

The solutions to the equation t^2-6t-40=0 are t=10,t=-4

Find the zeros of t^2-6t-40=0

The zeros of t^2-6t-40=0 are t=10,t=-4

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t^{2} - 6 t - 40 = 0

t = 10, t = - 4

Solution steps

t^{2} - 6 t - 40 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 40) = 14

t_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 1}

t = \frac{- ( - 6 ) + 14}{2 \cdot 1} : 10

t = \frac{- ( - 6 ) - 14}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

t = 10, t = - 4

\frac{1}{lo g _{4} ( 6 )} + \frac{1}{lo g _{9} ( 6 )}

x^{6} - y^{6}

\frac{8}{\frac{3}{2}}

∣ x + 8 ∣ = 12

4 (1 - x) = 9 (1 + 2 x) + 9

What are the solutions to the equation t^2-6t-40=0 ?
The solutions to the equation t^2-6t-40=0 are t=10,t=-4
Find the zeros of t^2-6t-40=0
The zeros of t^2-6t-40=0 are t=10,t=-4