What is expand ((t^2+2,3,t-1)\circ sqrt(2t)) ?

The solution to expand ((t^2+2,3,t-1)\circ sqrt(2t)) is sqrt(2)\circ sqrt(t)(t^2+2*3,,t-1)

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Popular >

expand ((t^2+2,3,t-1)\circ sqrt(2t))

expand

((t^{2} + 2, 3, t - 1) \circ 2 t)

2 \circ t (t^{2} + 2 \cdot 3,, t - 1)

Solution steps

((t^{2} + 2, 3, t - 1) \circ 2 t)

Apply radical rule:

ab = a b

2 t = 2 t

= 2 \circ t (t^{2} + 2 \cdot 3,, t - 1)

\frac{9.81 kn}{m ^{3}} (3.669 m^{2}) (2.5 m)

3.5 \cdot 1 0^{- 3} \cdot 68.4 6^{0.66}

3000 (1 + \frac{0.05}{4})^{- 4}

e^{- 54213}

π x^{2} x^{6} x^{14}

What is expand ((t^2+2,3,t-1)\circ sqrt(2t)) ?
The solution to expand ((t^2+2,3,t-1)\circ sqrt(2t)) is sqrt(2)\circ sqrt(t)(t^2+2*3,,t-1)