What are the solutions to the equation 1^2+x^2=sqrt(5)^2 ?

The solutions to the equation 1^2+x^2=sqrt(5)^2 are x=2,x=-2

Find the zeros of 1^2+x^2=sqrt(5)^2

The zeros of 1^2+x^2=sqrt(5)^2 are x=2,x=-2

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1^{2} + x^{2} = 5^{2}

x = 2, x = - 2

Solution steps

1^{2} + x^{2} = (5)^{2}

Move

1^{2}

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

- 8 x + 3 \geq 27 and - 13 x + 5 \geq 57

\frac{x ^{2} - 5 x}{9 - 2 x} < 0

- 9 < 2 x - 1 \leq 7

6 z^{2} - 11 z + 4

- \frac{24}{6}

What are the solutions to the equation 1^2+x^2=sqrt(5)^2 ?
The solutions to the equation 1^2+x^2=sqrt(5)^2 are x=2,x=-2
Find the zeros of 1^2+x^2=sqrt(5)^2
The zeros of 1^2+x^2=sqrt(5)^2 are x=2,x=-2