What is e^{-r(t-t)}*e^{(3S^2+3(r-D))} ?

The solution to e^{-r(t-t)}*e^{(3S^2+3(r-D))} is e^{3S^2+3(r-D)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify e^{-r(t-t)}*e^{(3S^2+3(r-D))}

simplify

e^{- r (t - t)} \cdot e^{(3 S^{2} + 3 (r - D))}

e^{3 S^{2} + 3 (r - D)}

Solution steps

e^{- r (t - t)} e^{(3 S^{2} + 3 (r - D))}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- r (t - t)} e^{3 S^{2} + 3 (r - D)} = e^{- r (t - t) + 3 S^{2} + 3 (r - D)}

= e^{- r (t - t) + 3 S^{2} + 3 (r - D)}

r (t - t) = 0

= e^{- 0 + 3 S^{2} + 3 (r - D)}

- 0 + 3 S^{2} + 3 (r - D) = 3 S^{2} + 3 (r - D)

= e^{3 S^{2} + 3 (r - D)}

e^{- \frac{11}{6}} (1 + \frac{11}{6})

4 e^{- 0} 0

x e^{x} \cdot e^{- \frac{x}{2}}

0.5 \cdot 5

What is e^{-r(t-t)}*e^{(3S^2+3(r-D))} ?
The solution to e^{-r(t-t)}*e^{(3S^2+3(r-D))} is e^{3S^2+3(r-D)}