What is (2e^{-j^{0.3}})*(3e^{j^{0.4}}) ?

The solution to (2e^{-j^{0.3}})*(3e^{j^{0.4}}) is 6e^{j^{0.4}-j^{0.3}}

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simplify (2e^{-j^{0.3}})*(3e^{j^{0.4}})

simplify

(2 e^{- j^{0.3}}) \cdot (3 e^{j^{0.4}})

6 e^{j^{0.4} - j^{0.3}}

Solution steps

(2 e^{- j^{0.3}}) (3 e^{j^{0.4}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- j^{0.3}} e^{j^{0.4}} = e^{- j^{0.3} + j^{0.4}}

= 2 \cdot 3 e^{- j^{0.3} + j^{0.4}}

Multiply the numbers:

2 \cdot 3 = 6

= 6 e^{j^{0.4} - j^{0.3}}

11924.59 (1.0599)^{- 5}

3.035 x 1 0^{- 3}

(2)^{2} e^{- \frac{2}{2}}

- 1 \cdot e^{- j^{2} (\frac{2 π}{4})}

(- 2 e^{3}) e^{- 2}

What is (2e^{-j^{0.3}})*(3e^{j^{0.4}}) ?
The solution to (2e^{-j^{0.3}})*(3e^{j^{0.4}}) is 6e^{j^{0.4}-j^{0.3}}