What is (12/10000)*2.72^{-(35/22)} ?

The solution to (12/10000)*2.72^{-(35/22)} is 3/(5^{9/11)*272*68^{13/22}}

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simplify (12/10000)*2.72^{-(35/22)}

simplify

(\frac{12}{10000}) \cdot 2.7 2^{- (\frac{35}{22})}

\frac{3}{5 ^{\frac{9}{11}} \cdot 272 \cdot 6 8 ^{\frac{13}{22}}}

Solution steps

(\frac{12}{10000}) \cdot 2.7 2^{- (\frac{35}{22})}

(\frac{12}{10000}) \cdot 2.7 2^{- (\frac{35}{22})} = \frac{12}{10000} \cdot 2.7 2^{- \frac{35}{22}}

= \frac{12}{10000} \cdot 2.7 2^{- \frac{35}{22}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

2.7 2^{- \frac{35}{22}} = \frac{1}{2.7 2 ^{\frac{35}{22}}}

= \frac{12}{10000} \cdot \frac{1}{2.7 2 ^{\frac{35}{22}}}

2.72 = \frac{68}{25}

= \frac{12}{10000} \cdot \frac{1}{( \frac{68}{25} ) ^{\frac{35}{22}}}

\frac{1}{( \frac{68}{25} ) ^{\frac{35}{22}}} = \frac{125 \cdot 5 ^{\frac{2}{11}}}{68 \cdot 6 8 ^{\frac{13}{22}}}

= \frac{12}{10000} \cdot \frac{125 \cdot 5 ^{\frac{2}{11}}}{68 \cdot 6 8 ^{\frac{13}{22}}}

Cancel

\frac{12}{10000} : \frac{3}{2500}

= \frac{3}{2500} \cdot \frac{125 \cdot 5 ^{\frac{2}{11}}}{68 \cdot 6 8 ^{\frac{13}{22}}}

\frac{3}{2500} \cdot \frac{125 \cdot 5 ^{\frac{2}{11}}}{68 \cdot 6 8 ^{\frac{13}{22}}} = \frac{3}{5 ^{\frac{9}{11}} \cdot 272 \cdot 6 8 ^{\frac{13}{22}}}

= \frac{3}{5 ^{\frac{9}{11}} \cdot 272 \cdot 6 8 ^{\frac{13}{22}}}

2000 e^{- \frac{24}{5}}

e^{- 0.12 (\frac{3}{12})} \cdot ((1 - 0.65227) \cdot 9.6)

(y \cdot x) (y^{2} \cdot x^{2})

200 \cdot (- 1.6) \cdot 1 0^{- 19}

82 (40 (2 π))^{2} (4.1 \cdot 1 0^{- 3})

What is (12/10000)*2.72^{-(35/22)} ?
The solution to (12/10000)*2.72^{-(35/22)} is 3/(5^{9/11)*272*68^{13/22}}