What is simplify-2.18*10^{-18}(1)(1/(1^2)-1/(3^2)) ?

The solution to simplify-2.18*10^{-18}(1)(1/(1^2)-1/(3^2)) is -(109)/(5^{18)*14745600}

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simplify-2.18*10^{-18}(1)(1/(1^2)-1/(3^2))

simplify

- 2.18 \cdot 1 0^{- 18} (1) (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}})

- \frac{109}{5 ^{18} \cdot 14745600}

Solution steps

- 2.18 \cdot 1 0^{- 18} (1) (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}})

Apply rule:

(a) = a

(1) = 1

= - 2.18 \cdot 1 0^{- 18} \cdot 1 \cdot (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}})

Multiply the numbers:

- 2.18 \cdot 1 = - 2.18

= - 2.18 \cdot 1 0^{- 18} (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}})

= - 1 0^{- 18} \cdot 2.18 (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 18} = \frac{1}{1 0 ^{18}}

= - \frac{1}{1 0 ^{18}} \cdot 2.18 (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}})

\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}} = \frac{8}{9}

= - \frac{1}{1 0 ^{18}} \cdot 2.18 \cdot \frac{8}{9}

2.18 = \frac{109}{50}

= - \frac{1}{1 0 ^{18}} \cdot \frac{109}{50} \cdot \frac{8}{9}

- \frac{1}{1 0 ^{18}} \cdot \frac{109}{50} \cdot \frac{8}{9} = - \frac{109}{5 ^{18} \cdot 14745600}

= - \frac{109}{5 ^{18} \cdot 14745600}

\frac{4.1172 \cdot ( 5.6 \cdot 1 0 ^{6} )}{8} (6.545 \cdot 1 0^{- 3})

2 π (9.1 \cdot 1 0^{- 31})

6.71 \cdot 1 0^{- 22} \cdot 0.082 \cdot (426 - 292)

0.002497 \cdot 1 0^{- 3}

2 \cdot 1.45 \cdot 159 \cdot 1 0^{- 9} \cdot 1

What is simplify-2.18*10^{-18}(1)(1/(1^2)-1/(3^2)) ?
The solution to simplify-2.18*10^{-18}(1)(1/(1^2)-1/(3^2)) is -(109)/(5^{18)*14745600}