What is \det(4((2pi)))*2^{-1}*1 ?

The solution to \det(4((2pi)))*2^{-1}*1 is 1/2 \det(8pi)

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simplify \det(4((2pi)))2^{-1}1

simplify

det (4 ((2 π))) \cdot 2^{- 1} \cdot 1

\frac{1}{2} det (8 π)

Solution steps

det (4 ((2 π))) \cdot 2^{- 1} \cdot 1

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 1 \cdot \frac{1}{2} det (4 \cdot 2 π)

Multiply the numbers:

4 \cdot 2 = 8

= 1 \cdot \frac{1}{2} det (8 π)

Multiply:

\frac{1}{2} \cdot 1 = \frac{1}{2}

= \frac{1}{2} det (8 π)

f (u) = cos^{2} (u) sin^{2} (u)

\frac{0.1 5 ^{2}}{0.0 5 ^{2}} \cdot 3

(u^{2} v) u v^{3}

What is \det(4((2pi)))*2^{-1}*1 ?
The solution to \det(4((2pi)))*2^{-1}*1 is 1/2 \det(8pi)