What is \sqrt[3]{(3x^4-2x^2-5)}^2 ?

The solution to \sqrt[3]{(3x^4-2x^2-5)}^2 is ((3x^4-2x^2-5))^{2/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify \sqrt[3]{(3x^4-2x^2-5)}^2

simplify

((3 x^{4} - 2 x^{2} - 5))^{\frac{2}{3}}

Solution steps

Apply radical rule:

= (((3 x^{4} - 2 x^{2} - 5))^{\frac{1}{3}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= ((3 x^{4} - 2 x^{2} - 5))^{\frac{1}{3} \cdot 2}

\frac{1}{3} \cdot 2 = \frac{2}{3}

= ((3 x^{4} - 2 x^{2} - 5))^{\frac{2}{3}}

(1 + 2 z) e^{- 2 z}

\frac{0.025}{19} \cdot 1. 1^{- 5}

d e (s - 6) (s - 1)^{- 3}

e^{- 1.352923}

((7^{3} \cdot 1 1^{5})^{\frac{1}{4}})^{^{'}}

What is \sqrt[3]{(3x^4-2x^2-5)}^2 ?
The solution to \sqrt[3]{(3x^4-2x^2-5)}^2 is ((3x^4-2x^2-5))^{2/3}