What is 2*(2e^{2x})(1+e^{2x})^2 ?

The solution to 2*(2e^{2x})(1+e^{2x})^2 is 4e^{2x}(e^{2x}+1)^2

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simplify 2*(2e^{2x})(1+e^{2x})^2

simplify

2 \cdot (2 e^{2 x}) (1 + e^{2 x})^{2}

4 e^{2 x} (e^{2 x} + 1)^{2}

Solution steps

2 (2 e^{2 x}) (1 + e^{2 x})^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= 2^{1 + 1} e^{2 x} (1 + e^{2 x})^{2}

Add the numbers:

1 + 1 = 2

= 2^{2} e^{2 x} (1 + e^{2 x})^{2}

2^{2} = 4

= 4 e^{2 x} (e^{2 x} + 1)^{2}

((- 4)^{2^{^{'}}})^{- 3^{^{'}}}

0.003 \cdot 2 \cdot 314 \cdot 2 \cdot 1 0^{5}

e^{- \frac{t}{2}} e^{\frac{t}{2}}

\frac{1}{2} \cdot (2.041 \cdot 1 0^{9}) (2.704 \cdot 1 0^{25})

2000 x (1.00175)^{x} (12 x^{5})

What is 2*(2e^{2x})(1+e^{2x})^2 ?
The solution to 2*(2e^{2x})(1+e^{2x})^2 is 4e^{2x}(e^{2x}+1)^2