What is 3e^{-e(3)}(3^2-16)(3^2+1)(3-1)^4 ?

The solution to 3e^{-e(3)}(3^2-16)(3^2+1)(3-1)^4 is -(3360)/(e^{3e)}

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simplify 3e^{-e(3)}(3^2-16)(3^2+1)(3-1)^4

simplify

3 e^{- e (3)} (3^{2} - 16) (3^{2} + 1) (3 - 1)^{4}

- \frac{3360}{e ^{3 e}}

Solution steps

3 e^{- e (3)} (3^{2} - 16) (3^{2} + 1) (3 - 1)^{4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 3 \cdot \frac{1}{e ^{3 e}} (3^{2} - 16) (3^{2} + 1) (3 - 1)^{4}

Subtract the numbers:

3 - 1 = 2

= 2^{4} \cdot 3 \cdot \frac{1}{e ^{3 e}} (3^{2} - 16) (3^{2} + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 3 ( 3 ^{2} - 16 ) ( 3 ^{2} + 1 ) \cdot 2 ^{4}}{e ^{e 3}}

1 \cdot 3 (3^{2} - 16) (3^{2} + 1) \cdot 2^{4} = - 2^{4} \cdot 210

= \frac{- 2 ^{4} \cdot 210}{e ^{3 e}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{210 \cdot 2 ^{4}}{e ^{e 3}}

210 \cdot 2^{4} = 3360

= - \frac{3360}{e ^{3 e}}

\frac{\frac{16}{2}}{π \cdot ( \frac{0.013}{2} ) ^{2}} \cdot 1 0^{- 3}

(6.8 \cdot 1 0^{- 5}) \cdot (0.12)

e^{- 2 \cdot l n (y)}

(\frac{m w}{πh})^{\frac{1}{2}} \cdot (\frac{πh}{m w})^{\frac{1}{2}}

43.09 \cdot 1 0^{- 6} (51)

What is 3e^{-e(3)}(3^2-16)(3^2+1)(3-1)^4 ?
The solution to 3e^{-e(3)}(3^2-16)(3^2+1)(3-1)^4 is -(3360)/(e^{3e)}