What is 75e^{-35/10 ((ln(14))/(15))} ?

The solution to 75e^{-35/10 ((ln(14))/(15))} is (75)/(e^{\frac{7ln(14)){30}}}

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simplify 75e^{-35/10 ((ln(14))/(15))}

simplify

75 e^{- \frac{35}{10} (\frac{l n ( 14 )}{15})}

\frac{75}{e ^{\frac{7 l n ( 14 )}{30}}}

Solution steps

75 e^{- \frac{35}{10} (\frac{l n ( 14 )}{15})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 75 \cdot \frac{1}{e ^{\frac{35}{10} \cdot \frac{l n ( 14 )}{15}}}

\frac{1}{e ^{\frac{35}{10} \cdot \frac{l n ( 14 )}{15}}} = \frac{1}{e ^{\frac{7 l n ( 14 )}{30}}}

= 75 \cdot \frac{1}{e ^{\frac{7 l n ( 14 )}{30}}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 75}{e ^{\frac{7 l n ( 14 )}{30}}}

Multiply the numbers:

1 \cdot 75 = 75

= \frac{75}{e ^{\frac{7 l n ( 14 )}{30}}}

\frac{3009}{55}

8 \cdot e^{- 1}

5^{9} x 3^{9} x 1 5^{- 7}

e^{- 0.0639}

2 e^{2 x} e^{3 x}

What is 75e^{-35/10 ((ln(14))/(15))} ?
The solution to 75e^{-35/10 ((ln(14))/(15))} is (75)/(e^{\frac{7ln(14)){30}}}