What is (2x^3y^4z^5)11x^2y^2z^2 ?

The solution to (2x^3y^4z^5)11x^2y^2z^2 is 22x^5y^6z^7

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simplify (2x^3y^4z^5)11x^2y^2z^2

simplify

(2 x^{3} y^{4} z^{5}) 11 x^{2} y^{2} z^{2}

22 x^{5} y^{6} z^{7}

Solution steps

(2 x^{3} y^{4} z^{5}) \cdot 11 x^{2} y^{2} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{3} x^{2} = x^{3 + 2}

= 2 y^{4} z^{5} \cdot 11 x^{3 + 2} y^{2} z^{2}

Add the numbers:

3 + 2 = 5

= 2 y^{4} z^{5} \cdot 11 x^{5} y^{2} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{4} y^{2} = y^{4 + 2}

= 2 z^{5} \cdot 11 x^{5} y^{4 + 2} z^{2}

Add the numbers:

4 + 2 = 6

= 2 z^{5} \cdot 11 x^{5} y^{6} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z^{5} z^{2} = z^{5 + 2}

= 2 \cdot 11 x^{5} y^{6} z^{5 + 2}

Add the numbers:

5 + 2 = 7

= 2 \cdot 11 x^{5} y^{6} z^{7}

Multiply the numbers:

2 \cdot 11 = 22

= 22 x^{5} y^{6} z^{7}

e^{40.91} \cdot 1.27 \cdot 1 0^{- 20}

- (e^{- 2 t})^{2} (e^{t})

(K - 1)^{2} (K - 2) K^{2}

What is (2x^3y^4z^5)11x^2y^2z^2 ?
The solution to (2x^3y^4z^5)11x^2y^2z^2 is 22x^5y^6z^7