What is the answer to (x^2+2x)^2-4x^2=x^4+4x^3 ?

The answer to (x^2+2x)^2-4x^2=x^4+4x^3 is True for all x

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(x^2+2x)^2-4x^2=x^4+4x^3

(x^{2} + 2 x)^{2} - 4 x^{2} = x^{4} + 4 x^{3}

True for all x

Solution steps

(x^{2} + 2 x)^{2} - 4 x^{2} = x^{4} + 4 x^{3}

Expand

(x^{2} + 2 x)^{2} - 4 x^{2} : x^{4} + 4 x^{3}

x^{4} + 4 x^{3} = x^{4} + 4 x^{3}

Subtract

x^{4} + 4 x^{3}

from both sides

x^{4} + 4 x^{3} - (x^{4} + 4 x^{3}) = x^{4} + 4 x^{3} - (x^{4} + 4 x^{3})

Simplify

0 = 0

Both sides are equal

True for all x

a \cdot 5 2^{2} - 1 = 0

\frac{2}{\frac{5}{2}}

\frac{3}{4} + 4

\frac{2}{7} - \frac{1}{2} \cdot \frac{4}{14} - (\frac{1}{2} - \frac{3}{4})

3 x (x + 1) - \frac{( x - 2 ) ^{2}}{2} = (x + 1) (x - 1) + 15

What is the answer to (x^2+2x)^2-4x^2=x^4+4x^3 ?
The answer to (x^2+2x)^2-4x^2=x^4+4x^3 is True for all x
Solve for x: (x^2+2x)^2-4x^2=x^4+4x^3
The solution is True for all x