What is (2x10^{-2})(6.28x10^9) ?

The solution to (2x10^{-2})(6.28x10^9) is 125600000x^2

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simplify (2x10^{-2})(6.28x10^9)

simplify

(2 x 1 0^{- 2}) (6.28 x 1 0^{9})

125600000 x^{2}

Solution steps

(2 x \cdot 1 0^{- 2}) (6.28 x \cdot 1 0^{9})

Simplify

2 x \cdot 1 0^{- 2} : \frac{x}{50}

= \frac{x}{50} \cdot 6.28 x \cdot 1 0^{9}

6.28 = \frac{157}{25}

= \frac{x}{50} \cdot \frac{157}{25} x \cdot 1 0^{9}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{x \cdot 157 x \cdot 1 0 ^{9}}{50 \cdot 25}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{x ^{2} \cdot 157 \cdot 1 0 ^{9}}{50 \cdot 25}

Cancel

\frac{x ^{2} \cdot 157 \cdot 1 0 ^{9}}{50 \cdot 25} : x^{2} \cdot 157 \cdot 5^{5} \cdot 2^{8}

= x^{2} \cdot 157 \cdot 5^{5} \cdot 2^{8}

5^{5} = 3125

= x^{2} \cdot 157 \cdot 3125 \cdot 2^{8}

2^{8} = 256

= x^{2} \cdot 157 \cdot 3125 \cdot 256

Multiply the numbers:

157 \cdot 3125 \cdot 256 = 125600000

= x^{2} \cdot 125600000

= 125600000 x^{2}

((1 + \frac{x}{360})^{4} (1 + \frac{3 x}{360})^{3})^{4}

- \frac{3}{2} \cdot e^{x^{2}} \cdot e^{- x^{2}}

3.74 \cdot 1 0^{- 19}

- 2.6 e^{(- 0.2 \cdot 5)}

2.26 \cdot 1 0^{- 6}

What is (2x10^{-2})(6.28x10^9) ?
The solution to (2x10^{-2})(6.28x10^9) is 125600000x^2