What is expand f(x,y)(xxx)^'(x,y)(x^9y^4-x^8y^3) ?

The solution to expand f(x,y)(xxx)^'(x,y)(x^9y^4-x^8y^3) is x^'x^'x^'(,xy)f(,xy)(x^9y^4-x^8y^3)

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expand f(x,y)(xxx)^'(x,y)(x^9y^4-x^8y^3)

expand

f (x, y) (xxx)^{^{'}} (x, y) (x^{9} y^{4} - x^{8} y^{3})

x^{'} x^{'} x^{'} (, x y) f (, x y) (x^{9} y^{4} - x^{8} y^{3})

Solution steps

f (x, y) (xxx)^{^{'}} (x, y) (x^{9} y^{4} - x^{8} y^{3})

Apply exponent rule:

(ab)^{c} = a^{c} b^{c}

(xxx)^{^{'}} = x^{^{'}} x^{^{'}} x^{^{'}}

= x^{^{^{'}}} x^{^{^{'}}} x^{^{^{'}}} f (, x y) (, x y) (x^{9} y^{4} - x^{8} y^{3})

e^{(- t)} t sin (2 t)

60 e^{- 0.811}

\frac{1}{μ} e^{- \frac{7}{μ}}

lo g_{10} (z) x y^{3}

e^{- 0.05 (\frac{2}{12})} (0.60204 \cdot 2.98044)

What is expand f(x,y)(xxx)^'(x,y)(x^9y^4-x^8y^3) ?
The solution to expand f(x,y)(xxx)^'(x,y)(x^9y^4-x^8y^3) is x^'x^'x^'(,xy)f(,xy)(x^9y^4-x^8y^3)