What are the solutions to the equation 7z^2+8z+3=3z^2 ?

The solutions to the equation 7z^2+8z+3=3z^2 are z=-1/2 ,z=-3/2

Find the zeros of 7z^2+8z+3=3z^2

The zeros of 7z^2+8z+3=3z^2 are z=-1/2 ,z=-3/2

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7 z^{2} + 8 z + 3 = 3 z^{2}

z = - \frac{1}{2}, z = - \frac{3}{2}

Decimal Notation

z = - 0.5, z = - 1.5

Solution steps

7 z^{2} + 8 z + 3 = 3 z^{2}

Move

3 z^{2}

to the left side

4 z^{2} + 8 z + 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

z_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- 8 + 4}{2 \cdot 4}, z_{2} = \frac{- 8 - 4}{2 \cdot 4}

z = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

z = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

z = - \frac{1}{2}, z = - \frac{3}{2}

(- 1)^{\frac{1}{4}}

0 - (- 4)

\frac{1}{3} \cdot 5

y^{2} - 13 y + 36 = 0

\frac{6 ^{9}}{6 ^{7}}

What are the solutions to the equation 7z^2+8z+3=3z^2 ?
The solutions to the equation 7z^2+8z+3=3z^2 are z=-1/2 ,z=-3/2
Find the zeros of 7z^2+8z+3=3z^2
The zeros of 7z^2+8z+3=3z^2 are z=-1/2 ,z=-3/2