What is 1.95*10^{-5}kgm^{-2}s^{-1} ?

The solution to 1.95*10^{-5}kgm^{-2}s^{-1} is (1.95kg)/(100000m^2s)

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simplify 1.95*10^{-5}kgm^{-2}s^{-1}

simplify

1.95 \cdot 1 0^{- 5} k g m^{- 2} s^{- 1}

\frac{1.95 k g}{100000 m ^{2} s}

Solution steps

1.95 \cdot 1 0^{- 5} k g m^{- 2} s^{- 1}

1 0^{- 5} = \frac{1}{100000}

= 1.95 \cdot \frac{1}{100000} k g m^{- 2} s^{- 1}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

m^{- 2} = \frac{1}{m ^{2}}

= 1.95 \cdot \frac{1}{100000} k g \frac{1}{m ^{2}} s^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

s^{- 1} = \frac{1}{s}

= 1.95 \cdot \frac{1}{100000} k g \frac{1}{m ^{2}} \cdot \frac{1}{s}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1.95 \cdot 1 \cdot k g \cdot 1 \cdot 1}{100000 m ^{2} s}

Multiply the numbers:

1.95 \cdot 1 \cdot 1 \cdot 1 = 1.95

= \frac{1.95 k g}{100000 m ^{2} s}

e^{- x} (e^{x} x - e^{x} + 2 x + c)

e^{- \frac{3}{5} l n (x)}

30 (22) e^{- \frac{1}{11} (22)}

What is 1.95*10^{-5}kgm^{-2}s^{-1} ?
The solution to 1.95*10^{-5}kgm^{-2}s^{-1} is (1.95kg)/(100000m^2s)