What are the solutions to the equation x^2+6x=9 ?

The solutions to the equation x^2+6x=9 are x=3(sqrt(2)-1),x=-3(1+sqrt(2))

Find the zeros of x^2+6x=9

The zeros of x^2+6x=9 are x=3(sqrt(2)-1),x=-3(1+sqrt(2))

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x^{2} + 6 x = 9

x = 3 (2 - 1), x = - 3 (1 + 2)

Decimal Notation

x = 1.24264 \dots, x = - 7.24264 \dots

Solution steps

x^{2} + 6 x = 9

Move

9

to the left side

x^{2} + 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 9) = 62

x_{1, 2} = \frac{- 6 \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 6 2}{2 \cdot 1}

x = \frac{- 6 + 6 2}{2 \cdot 1} : 3 (2 - 1)

x = \frac{- 6 - 6 2}{2 \cdot 1} : - 3 (1 + 2)

The solutions to the quadratic equation are:

x = 3 (2 - 1), x = - 3 (1 + 2)

- 7 x + 9 = 2 x - 99

\frac{3}{5} \cdot \frac{1}{7}

3 - 3

lo g_{2} (20) - lo g_{2} (5)

2 (3 v - 7) = 34

What are the solutions to the equation x^2+6x=9 ?
The solutions to the equation x^2+6x=9 are x=3(sqrt(2)-1),x=-3(1+sqrt(2))
Find the zeros of x^2+6x=9
The zeros of x^2+6x=9 are x=3(sqrt(2)-1),x=-3(1+sqrt(2))