What is ((x^4)/2+(x^4)/(12))e^{-x} ?

The solution to ((x^4)/2+(x^4)/(12))e^{-x} is (7x^4)/(12e^x)

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simplify ((x^4)/2+(x^4)/(12))e^{-x}

simplify

(\frac{x ^{4}}{2} + \frac{x ^{4}}{12}) e^{- x}

\frac{7 x ^{4}}{12 e ^{x}}

Solution steps

(\frac{x ^{4}}{2} + \frac{x ^{4}}{12}) e^{- x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{x}} (\frac{x ^{4}}{2} + \frac{x ^{4}}{12})

Join

\frac{x ^{4}}{2} + \frac{x ^{4}}{12} : \frac{7 x ^{4}}{12}

= \frac{1}{e ^{x}} \cdot \frac{7 x ^{4}}{12}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{7 x ^{4} \cdot 1}{12 e ^{x}}

Multiply the numbers:

7 \cdot 1 = 7

= \frac{7 x ^{4}}{12 e ^{x}}

0.85014 \cdot 6^{- 1}

1.85 \cdot (5.67 \cdot 1 0^{- 8}) \cdot (31 3^{4} - 30 6^{4})

(4 π \cdot 1 0^{- 7}) (3.83 \cdot 1 0^{- 4})

\frac{1}{2 ^{x} \cdot ln ( 2 )} \cdot \frac{1}{2} \cdot (2^{x})^{2}

What is ((x^4)/2+(x^4)/(12))e^{-x} ?
The solution to ((x^4)/2+(x^4)/(12))e^{-x} is (7x^4)/(12e^x)