What is xe^{-x}(e^{-t}ln(t)x) ?

The solution to xe^{-x}(e^{-t}ln(t)x) is e^{-x-t}x^2ln(t)

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simplify xe^{-x}(e^{-t}ln(t)x)

simplify

x e^{- x} (e^{- t} ln (t) x)

e^{- x - t} x^{2} ln (t)

Solution steps

x e^{- x} (e^{- t} ln (t) x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- x} e^{- t} = e^{- x - t}

= x e^{- x - t} ln (t) x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

xx = x^{1 + 1}

= e^{- x - t} ln (t) x^{1 + 1}

Add the numbers:

1 + 1 = 2

= e^{- x - t} ln (t) x^{2}

3.3335 \cdot 1 0^{- 12}

\frac{2}{40001}

1.32 x 1 0^{- 5}

(3^{- 1} + 3^{- 2})^{- 1^{^{'}}}^{^{'}}

(7 r^{8} t^{6}) (\frac{1}{7} s^{10} t^{9})

What is xe^{-x}(e^{-t}ln(t)x) ?
The solution to xe^{-x}(e^{-t}ln(t)x) is e^{-x-t}x^2ln(t)