What are the solutions to the equation x^2-x=0 ?

The solutions to the equation x^2-x=0 are x=1,x=0

Find the zeros of x^2-x=0

The zeros of x^2-x=0 are x=1,x=0

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x^{2} - x = 0

x = 1, x = 0

Solution steps

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

2^{n} - 2^{n - 1}

∣ 3 (x - 1) + 2 ∣ \leq 20

ln (x y)

2 (4 u - 7) = 66

81 x^{2} - 36 = 0

What are the solutions to the equation x^2-x=0 ?
The solutions to the equation x^2-x=0 are x=1,x=0
Find the zeros of x^2-x=0
The zeros of x^2-x=0 are x=1,x=0