What is (2cis(pi/6))^{-1} ?

The solution to (2cis(pi/6))^{-1} is 3/(piics)

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simplify (2cis(pi/6))^{-1}

simplify

(2 c i s (\frac{π}{6}))^{- 1}

\frac{3}{πi cs}

Solution steps

(2 c i s (\frac{π}{6}))^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{2 \cdot \frac{π}{6} i cs}

Multiply

2 c i s \frac{π}{6} : \frac{πi cs}{3}

= \frac{1}{\frac{πi cs}{3}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{3}{πi cs}

e^{- λ t}

e^{- (0.00062206) \cdot 1000}

\frac{( 1 - x ^{2} ) ^{2}}{( ( 1.41 x ) ^{2} + ( 1 - x ^{2} ) ^{2} ) ^{2}}

- x^{2} e^{- x} [1 + \frac{2}{2}]