What is (1.6*10^{-19})(4.2*10^{-12}) ?

The solution to (1.6*10^{-19})(4.2*10^{-12}) is (21)/(5^{33)*268435456}

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simplify (1.610^{-19})(4.210^{-12})

simplify

(1.6 \cdot 1 0^{- 19}) (4.2 \cdot 1 0^{- 12})

\frac{21}{5 ^{33} \cdot 268435456}

Decimal Notation

6.72 E - 31

Solution steps

(1.6 \cdot 1 0^{- 19}) (4.2 \cdot 1 0^{- 12})

Simplify

1.6 \cdot 1 0^{- 19} : \frac{1}{5 ^{20} \cdot 65536}

= \frac{1}{5 ^{20} \cdot 65536} \cdot 4.2 \cdot 1 0^{- 12}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= \frac{1}{5 ^{20} \cdot 65536} \cdot 4.2 \cdot \frac{1}{1 0 ^{12}}

\frac{1}{5 ^{20} \cdot 65536} \cdot 4.2 \cdot \frac{1}{1 0 ^{12}} = \frac{4.2}{5 ^{20} \cdot 1 0 ^{12} \cdot 65536}

= \frac{4.2}{5 ^{20} \cdot 1 0 ^{12} \cdot 65536}

\frac{4.2}{5 ^{20} \cdot 1 0 ^{12} \cdot 65536} = \frac{42}{655360 \cdot 5 ^{20} \cdot 1 0 ^{12}}

= \frac{42}{655360 \cdot 5 ^{20} \cdot 1 0 ^{12}}

Factor the number:

42 = 2 \cdot 21

= \frac{2 \cdot 21}{655360 \cdot 5 ^{20} \cdot 1 0 ^{12}}

Factor the number:

655360 = 2 \cdot 327680

= \frac{2 \cdot 21}{2 \cdot 327680 \cdot 5 ^{20} \cdot 1 0 ^{12}}

Cancel the common factor:

2

= \frac{21}{327680 \cdot 5 ^{20} \cdot 1 0 ^{12}}

327680 \cdot 5^{20} \cdot 1 0^{12} = 5^{33} \cdot 268435456

= \frac{21}{5 ^{33} \cdot 268435456}

\frac{( 600 ) ^{2}}{( 9.8 ) ^{2}}

16 (2 π x)^{2}

(x + 3 y^{222} - 27) 432 s df gg hjk l \cdot 0

(x + 3 y^{222} - 27) 432 s df gg hjk l \cdot 1

What is (1.6*10^{-19})(4.2*10^{-12}) ?
The solution to (1.6*10^{-19})(4.2*10^{-12}) is (21)/(5^{33)*268435456}