What is (x+3y^{222}-27)432sdfgghjkl*1 ?

The solution to (x+3y^{222}-27)432sdfgghjkl*1 is 432kljsg^2hdf(x+3y^{222}-27)

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simplify (x+3y^{222}-27)432sdfgghjkl*1

simplify

(x + 3 y^{222} - 27) 432 s df gg hjk l \cdot 1

432 k l j s g^{2} h df (x + 3 y^{222} - 27)

Solution steps

(x + 3 y^{222} - 27) \cdot 432 s df gg hjk l \cdot 1

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

gg = g^{1 + 1}

= (x + 3 y^{222} - 27) \cdot 432 s df g^{1 + 1} hjk l \cdot 1

Add the numbers:

1 + 1 = 2

= (x + 3 y^{222} - 27) \cdot 432 s df g^{2} hjk l \cdot 1

Multiply the numbers:

432 \cdot 1 = 432

= 432 k l j s g^{2} h (x + 3 y^{222} - 27) df

100 e^{- 0.075 \cdot 20}

5.67 \cdot 1 0^{- 8} \cdot 31 7^{4}

e^{- 0.303}

What is (x+3y^{222}-27)432sdfgghjkl*1 ?
The solution to (x+3y^{222}-27)432sdfgghjkl*1 is 432kljsg^2hdf(x+3y^{222}-27)