What is (fg\circ f)((3x-2)/5)^3 ?

The solution to (fg\circ f)((3x-2)/5)^3 is (\circ f^2g(3x-2)^3)/(125)

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simplify (fg\circ f)((3x-2)/5)^3

simplify

(f g \circ f) (\frac{3 x - 2}{5})^{3}

\frac{\circ f ^{2} g ( 3 x - 2 ) ^{3}}{125}

Solution steps

(f g \circ f) (\frac{3 x - 2}{5})^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ff = f^{1 + 1}

= g \circ f^{1 + 1} (\frac{3 x - 2}{5})^{3}

Add the numbers:

1 + 1 = 2

= g \circ f^{2} (\frac{3 x - 2}{5})^{3}

(\frac{3 x - 2}{5})^{3} = \frac{( 3 x - 2 ) ^{3}}{5 ^{3}}

= \circ f^{2} g \frac{( 3 x - 2 ) ^{3}}{5 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 x - 2 ) ^{3} g \circ f ^{2}}{5 ^{3}}

5^{3} = 125

= \frac{\circ f ^{2} g ( 3 x - 2 ) ^{3}}{125}

\frac{1}{2 \cdot π} \cdot e^{- 0.5 \cdot 0}

1.28 x 1 0^{- 5} \cdot \frac{180}{π}

11.82 \cdot 1 0^{- 6}

e^{- 2 l n (1 - y)}

e^{- \frac{1}{60} \cdot 75}

What is (fg\circ f)((3x-2)/5)^3 ?
The solution to (fg\circ f)((3x-2)/5)^3 is (\circ f^2g(3x-2)^3)/(125)