What is 1/(e^{y^{-α)}}*(e^{y^{-α}})/(e^{y^{-α)}} ?

The solution to 1/(e^{y^{-α)}}*(e^{y^{-α}})/(e^{y^{-α)}} is 1/(e^{y^{-α)}}

Popular >

simplify 1/(e^{y^{-α)}}*(e^{y^{-α}})/(e^{y^{-α)}}

simplify

\frac{1}{e ^{y^{- α}}} \cdot \frac{e ^{y^{- α}}}{e ^{y^{- α}}}

\frac{1}{e ^{y^{- α}}}

Solution steps

\frac{1}{e ^{y^{- α}}} \cdot \frac{e ^{y^{- α}}}{e ^{y^{- α}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= e^{y^{- α} - y^{- α}} \frac{1}{e ^{y^{- α}}}

e^{y^{- α} - y^{- α}} = 1

= 1 \cdot \frac{1}{e ^{y^{- α}}}

Multiply:

\frac{1}{e ^{y^{- α}}} \cdot 1 = \frac{1}{e ^{y^{- α}}}

= \frac{1}{e ^{y^{- α}}}

(23.73) (8.85 \cdot 1 0^{- 12})

3 s e^{- s t} (2 s sin (3 t) + cos (3 t))

11.64 \cdot 5000.55 \cdot 1 0^{- 3}

\frac{a + 2 b}{a - 2 b}

(0.5) (0.5) (\frac{2.326}{0.03})^{2}

What is 1/(e^{y^{-α)}}*(e^{y^{-α}})/(e^{y^{-α)}} ?
The solution to 1/(e^{y^{-α)}}*(e^{y^{-α}})/(e^{y^{-α)}} is 1/(e^{y^{-α)}}