What is (234349.59507)(0.01958)(8.854*10^{-12}) ?

The solution to (234349.59507)(0.01958)(8.854*10^{-12}) is (4.06272E15)/(100000000000*10^{12)}

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simplify (234349.59507)(0.01958)(8.854*10^{-12})

simplify

(234349.59507) (0.01958) (8.854 \cdot 1 0^{- 12})

\frac{4.06272 E 15}{100000000000 \cdot 1 0 ^{12}}

Decimal Notation

4.06272 E - 8

Solution steps

(234349.59507) (0.01958) (8.854 \cdot 1 0^{- 12})

(234349.59507) (0.01958) (8.854 \cdot 1 0^{- 12}) = 234349.59507 \cdot 0.01958 (8.854 \cdot 1 0^{- 12})

= 234349.59507 \cdot 0.01958 \cdot 8.854 \cdot 1 0^{- 12}

Multiply the numbers:

234349.59507 \cdot 0.01958 \cdot 8.854 = 40627.15514 \dots

= 40627.15514 \dots \cdot 1 0^{- 12}

= 1 0^{- 12} \cdot 40627.15514 \dots

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= \frac{1}{1 0 ^{12}} \cdot 40627.15514 \dots

\frac{1}{1 0 ^{12}} \cdot 40627.15514 \dots = \frac{40627.15514 \dots}{1 0 ^{12}}

= \frac{40627.15514 \dots}{1 0 ^{12}}

\frac{40627.15514 \dots}{1 0 ^{12}} = \frac{4.06272 E 15}{100000000000 \cdot 1 0 ^{12}}

= \frac{4.06272 E 15}{100000000000 \cdot 1 0 ^{12}}

x \cdot \frac{yz}{2 ( e + x )}

8 e^{2 t} \cdot 2 e^{3 t}

e^{L \cdot (e^{t} - 1)} \cdot L e^{- Lx}

- 3.3 e^{- 0.3184}

What is (234349.59507)(0.01958)(8.854*10^{-12}) ?
The solution to (234349.59507)(0.01958)(8.854*10^{-12}) is (4.06272E15)/(100000000000*10^{12)}