What are the solutions to the equation 0=x^2-41x+238 ?

The solutions to the equation 0=x^2-41x+238 are x=34,x=7

Find the zeros of 0=x^2-41x+238

The zeros of 0=x^2-41x+238 are x=34,x=7

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0 = x^{2} - 41 x + 238

x = 34, x = 7

Solution steps

0 = x^{2} - 41 x + 238

Switch sides

x^{2} - 41 x + 238 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 1 \cdot 238}{2 \cdot 1}

(- 41)^{2} - 4 \cdot 1 \cdot 238 = 27

x_{1, 2} = \frac{- ( - 41 ) \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 27}{2 \cdot 1}, x_{2} = \frac{- ( - 41 ) - 27}{2 \cdot 1}

x = \frac{- ( - 41 ) + 27}{2 \cdot 1} : 34

x = \frac{- ( - 41 ) - 27}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 34, x = 7

\frac{- 9 x y ^{5} z ^{3}}{36 x y ^{4} z ^{5}}

5 x (8 - x) = 10

\frac{x}{3} \leq x + 2

(\frac{1}{2})^{\frac{2}{3}}

\frac{x ^{6}}{x ^{- 2}}

What are the solutions to the equation 0=x^2-41x+238 ?
The solutions to the equation 0=x^2-41x+238 are x=34,x=7
Find the zeros of 0=x^2-41x+238
The zeros of 0=x^2-41x+238 are x=34,x=7