What is expand 9(-4ab^2c^{-3})^{-3} ?

The solution to expand 9(-4ab^2c^{-3})^{-3} is -(9c^9)/(64a^3b^6)

Popular >

expand 9(-4ab^2c^{-3})^{-3}

expand

9 (- 4 a b^{2} c^{- 3})^{- 3}

- \frac{9 c ^{9}}{64 a ^{3} b ^{6}}

Solution steps

9 (- 4 a b^{2} c^{- 3})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 9 \cdot \frac{1}{( - 4 a b ^{2} c ^{- 3} ) ^{3}}

\frac{1}{( - 4 a b ^{2} c ^{- 3} ) ^{3}} = - \frac{c ^{9}}{4 ^{3} a ^{3} b ^{6}}

= 9 (- \frac{c ^{9}}{4 ^{3} a ^{3} b ^{6}})

Remove parentheses:

(- a) = - a

= - 9 \cdot \frac{c ^{9}}{4 ^{3} a ^{3} b ^{6}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{c ^{9} \cdot 9}{4 ^{3} a ^{3} b ^{6}}

4^{3} = 64

= - \frac{9 c ^{9}}{64 a ^{3} b ^{6}}

634183.24 \cdot (1 + 0.1)^{- 3}

e^{- 3 \cdot 1}

e^{- (0.0009505 \cdot 1500)}

e^{- 0.16 \cdot 31}

(u^{1} u^{2} u^{3}) \cdot (v^{1} v^{2} v^{3}) l e f t (w^{1}, w^{2}, w^{3})

What is expand 9(-4ab^2c^{-3})^{-3} ?
The solution to expand 9(-4ab^2c^{-3})^{-3} is -(9c^9)/(64a^3b^6)