What is the answer to 4(y+1)-y=3(y-1)+7 ?

The answer to 4(y+1)-y=3(y-1)+7 is True for all y

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4(y+1)-y=3(y-1)+7

4 (y + 1) - y = 3 (y - 1) + 7

True for all y

Solution steps

4 (y + 1) - y = 3 (y - 1) + 7

Expand

4 (y + 1) - y : 3 y + 4

Expand

3 (y - 1) + 7 : 3 y + 4

3 y + 4 = 3 y + 4

Move

4

to the right side

3 y = 3 y

Move

3 y

to the left side

0 = 0

Both sides are equal

True for all y

9 \cdot - 1 \cdot 2

2 x = - \frac{π}{2}

∣ 5 x - 7 ∣ = ∣ 3 x - 5 ∣

\frac{7 x}{2} + \frac{1}{2} = - \frac{2}{3} - x

\frac{2 x + 2 y}{x ^{2} - 2 x y + y ^{2}} \cdot \frac{x ^{2} - x y}{7 y + 7 x}

What is the answer to 4(y+1)-y=3(y-1)+7 ?
The answer to 4(y+1)-y=3(y-1)+7 is True for all y
Solve for y: 4(y+1)-y=3(y-1)+7
The solution is True for all y