What is the answer to 3c+2(c+4)=128 ?

The answer to 3c+2(c+4)=128 is c=24

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3c+2(c+4)=128

3 c + 2 (c + 4) = 128

c = 24

Solution steps

3 c + 2 (c + 4) = 128

Expand

2 (c + 4) : 2 c + 8

3 c + 2 c + 8 = 128

Add similar elements:

3 c + 2 c = 5 c

5 c + 8 = 128

Move

8

to the right side

5 c = 120

Divide both sides by

5

c = 24

\frac{2}{4} + \frac{1}{3}

7 - x \leq 7

9 - 4

\frac{( x ^{3} )}{x ^{8}}

lo g_{6} (36)