What is (0.0524)e^{-(3.7*10^{-5})(7920)} ?

The solution to (0.0524)e^{-(3.7*10^{-5})(7920)} is 0.03908…

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simplify (0.0524)e^{-(3.7*10^{-5})(7920)}

simplify

(0.0524) e^{- (3.7 \cdot 1 0^{- 5}) (7920)}

0.03908 \dots

Solution steps

(0.0524) e^{- (3.7 \cdot 1 0^{- 5}) (7920)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 0.0524 \cdot \frac{1}{e ^{1 0^{- 5} \cdot 7920 \cdot 3.7}}

\frac{1}{e ^{3.7 \cdot 1 0^{- 5} \cdot 7920}} = \frac{1}{e ^{\frac{3663}{12500}}}

= 0.0524 \cdot \frac{1}{e ^{\frac{3663}{12500}}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 0.0524}{e ^{\frac{3663}{12500}}}

Multiply the numbers:

1 \cdot 0.0524 = 0.0524

= \frac{0.0524}{e ^{\frac{3663}{12500}}}

Convert element to a decimal form

e^{\frac{3663}{12500}} = 1.34049 \dots

= \frac{0.0524}{1.34049 \dots}

Divide the numbers:

\frac{0.0524}{1.34049 \dots} = 0.03908 \dots

= 0.03908 \dots

[\frac{1}{0.011} + \frac{0.7722}{0.0181}]^{- 1} \cdot 1.6

50 e^{- 0.0526 (x)}

e^{- n (\frac{1}{β} - \frac{1}{x}) x}

e^{- (l n^{2} (x))}

What is (0.0524)e^{-(3.7*10^{-5})(7920)} ?
The solution to (0.0524)e^{-(3.7*10^{-5})(7920)} is 0.03908…