What is 10^{-12}(log_{10}(7.418)) ?

The solution to 10^{-12}(log_{10}(7.418)) is (log_{10}(7418)-3)/(10^{12)}

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simplify 10^{-12}(log_{10}(7.418))

simplify

1 0^{- 12} (lo g_{10} (7.418))

\frac{lo g _{10} ( 7418 ) - 3}{1 0 ^{12}}

Decimal Notation

8.70287 E - 13

Solution steps

1 0^{- 12} (lo g_{10} (7.418))

Apply rule:

(a) = a

(lo g_{10} (7.418)) = lo g_{10} (7.418)

= 1 0^{- 12} lo g_{10} (7.418)

lo g_{10} (7.418) = lo g_{10} (7418) - 3

= 1 0^{- 12} (lo g_{10} (7418) - 3)

Simplify

1 0^{- 12} (lo g_{10} (7418) - 3) : \frac{1}{1 0 ^{12}} lo g_{10} (7418) - \frac{3}{1 0 ^{12}}

= \frac{1}{1 0 ^{12}} lo g_{10} (7418) - \frac{3}{1 0 ^{12}}

\frac{1}{1 0 ^{12}} lo g_{10} (7418) - \frac{3}{1 0 ^{12}} = \frac{lo g _{10} ( 7418 ) - 3}{1 0 ^{12}}

= \frac{lo g _{10} ( 7418 ) - 3}{1 0 ^{12}}

(12 x^{4} y^{4}) (2 x y^{2})

e^{- 3 t} t sin (h) (5 t)

3 (3)^{2} \cdot 0.03

10 x^{3} x

e^{- \frac{1500}{1350}}

What is 10^{-12}(log_{10}(7.418)) ?
The solution to 10^{-12}(log_{10}(7.418)) is (log_{10}(7418)-3)/(10^{12)}