What are the solutions to the equation -16t^2+288=0 ?

The solutions to the equation -16t^2+288=0 are t=3sqrt(2),t=-3sqrt(2)

Find the zeros of -16t^2+288=0

The zeros of -16t^2+288=0 are t=3sqrt(2),t=-3sqrt(2)

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- 16 t^{2} + 288 = 0

t = 32, t = - 32

Solution steps

- 16 t^{2} + 288 = 0

Move

288

to the right side

- 16 t^{2} = - 288

Divide both sides by

- 16

t^{2} = 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 18, t = - 18

18 = 32

- 18 = - 32

t = 32, t = - 32

\frac{3 !}{2 ! 1 !}

\frac{4}{10} + \frac{3}{100}

2 d^{2} + 11 d + 9

x - 4 = 52

∣ 1 - 4 x ∣ > 6

What are the solutions to the equation -16t^2+288=0 ?
The solutions to the equation -16t^2+288=0 are t=3sqrt(2),t=-3sqrt(2)
Find the zeros of -16t^2+288=0
The zeros of -16t^2+288=0 are t=3sqrt(2),t=-3sqrt(2)