What is the (e^{5sqrt(x)})^' ?

The (e^{5sqrt(x)})^' is (5e^{5sqrt(x)})/(2sqrt(x))

What is the first (e^{5sqrt(x)})^' ?

The first (e^{5sqrt(x)})^' is (5e^{5sqrt(x)})/(2sqrt(x))

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(e^{5 x})^{^{'}}

\frac{5 e ^{5 x}}{2 x}

Solution steps

(e^{5 x})^{'}

Apply the chain rule:

e^{5 x} (5 x)^{'}

= e^{5 x} (5 x)^{'}

(5 x)^{'} = \frac{5}{2 x}

= e^{5 x} \frac{5}{2 x}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 e ^{5 x}}{2 x}

\frac{5}{21}

- 1 e^{- 0.5 \cdot (- 2.5)}

25 e^{- \frac{Rt}{L}}

e^{- 0.5 l n (x^{3} + x)}

e^{- 4 x^{2}}

What is the (e^{5sqrt(x)})^' ?
The (e^{5sqrt(x)})^' is (5e^{5sqrt(x)})/(2sqrt(x))
What is the first (e^{5sqrt(x)})^' ?
The first (e^{5sqrt(x)})^' is (5e^{5sqrt(x)})/(2sqrt(x))