What is parciales 9/(x^2-3x) ?

The solution to parciales 9/(x^2-3x) is (9eclipa^2rs)/(x^2-3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify parciales 9/(x^2-3x)

simplify

p a rc ia l es \frac{9}{x ^{2} - 3 x}

\frac{9 ec l i p a ^{2} rs}{x ^{2} - 3 x}

Solution steps

p a rc ia l es \frac{9}{x ^{2} - 3 x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

= p rc i a^{1 + 1} l es \frac{9}{x ^{2} - 3 x}

Add the numbers:

1 + 1 = 2

= p rc i a^{2} l es \frac{9}{x ^{2} - 3 x}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{9 p rc i a ^{2} l es}{x ^{2} - 3 x}

e^{- e^{l n (x)}}

R^{2} + (\frac{h}{2})^{2}^{2} \cdot h \cdot π

(25 x^{2 y}) (10 x y^{2})

1000 \cdot 7.41 \cdot (1 0^{- 4}) \cdot 9.8

(- 1)^{x} (- 3)^{x}

What is parciales 9/(x^2-3x) ?
The solution to parciales 9/(x^2-3x) is (9eclipa^2rs)/(x^2-3x)