What is e^{-2x}*2e^{2x}cos(2x)sec(2x) ?

The solution to e^{-2x}*2e^{2x}cos(2x)sec(2x) is 2cos(2x)sec(2x)

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simplify e^{-2x}*2e^{2x}cos(2x)sec(2x)

simplify

e^{- 2 x} \cdot 2 e^{2 x} cos (2 x) sec (2 x)

2 cos (2 x) sec (2 x)

Solution steps

e^{- 2 x} \cdot 2 e^{2 x} cos (2 x) sec (2 x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- 2 x} e^{2 x} = e^{- 2 x + 2 x}

= 2 e^{- 2 x + 2 x} cos (2 x) sec (2 x)

Add similar elements:

- 2 x + 2 x = 0

= 2 e^{0} cos (2 x) sec (2 x)

Apply rule

a^{0} = 1, a \neq = 0

e^{0} = 1

= 2 \cdot 1 \cdot cos (2 x) sec (2 x)

Multiply the numbers:

2 \cdot 1 = 2

= 2 cos (2 x) sec (2 x)

\frac{e ^{8 x}}{e ^{- 8 x}}

9.7 \cdot 1 0^{- 4}

20 e^{- 3 x} \cdot e^{- 5 x}

0.0005 \cdot 8.85 \cdot 1 0^{- 12}

(4.1 \cdot 1 0^{- 5}) (1 \cdot 1 0^{- 8})

What is e^{-2x}*2e^{2x}cos(2x)sec(2x) ?
The solution to e^{-2x}*2e^{2x}cos(2x)sec(2x) is 2cos(2x)sec(2x)