What is (2000)(1.602*10^{-19}) ?

The solution to (2000)(1.602*10^{-19}) is (801)/(5^{19)*131072}

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simplify (2000)(1.602*10^{-19})

simplify

(2000) (1.602 \cdot 1 0^{- 19})

\frac{801}{5 ^{19} \cdot 131072}

Decimal Notation

3.204 E - 16

Solution steps

(2000) (1.602 \cdot 1 0^{- 19})

Apply rule:

(a) = a

(2000) = 2000

= 2000 \cdot 1.602 \cdot 1 0^{- 19}

Multiply the numbers:

2000 \cdot 1.602 = 3204

= 3204 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 3204

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 3204

\frac{1}{1 0 ^{19}} \cdot 3204 = \frac{801}{5 ^{19} \cdot 131072}

= \frac{801}{5 ^{19} \cdot 131072}

2.05 \cdot 73 0^{- 0.18}

(5^{\frac{3 x}{6}})^{- 6 = 1}

(e^{- 2 x}) (e^{- 2 x} - 2 x)

\frac{2}{2}

e^{- 2 l n (x + 2 y)}

What is (2000)(1.602*10^{-19}) ?
The solution to (2000)(1.602*10^{-19}) is (801)/(5^{19)*131072}