What is e^{-((ln(k))/((k-1)))} ?

The solution to e^{-((ln(k))/((k-1)))} is 1/(k^{\frac{1){k-1}}}

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simplify e^{-((ln(k))/((k-1)))}

simplify

e^{- (\frac{l n ( k )}{( k - 1 )})}

\frac{1}{k ^{\frac{1}{k - 1}}}

Solution steps

e^{- (\frac{l n ( k )}{( k - 1 )})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{l n ( k )}{k - 1}}}

e^{\frac{l n ( k )}{k - 1}} = k^{\frac{1}{k - 1}}

= \frac{1}{k ^{\frac{1}{k - 1}}}

5.97379 \cdot 1 0^{23} \cdot (5.0279 \cdot 1 0^{- 31})

(1870) (1.6 \cdot 1 0^{- 19})

e \cdot e^{- y}

e^{- 4 x} \cdot e^{- x}

What is e^{-((ln(k))/((k-1)))} ?
The solution to e^{-((ln(k))/((k-1)))} is 1/(k^{\frac{1){k-1}}}