What are the solutions to the equation (x+9)^2=-25 ?

The solutions to the equation (x+9)^2=-25 are x=5i-9,x=-5i-9

Find the zeros of (x+9)^2=-25

The zeros of (x+9)^2=-25 are x=5i-9,x=-5i-9

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(x + 9)^{2} = - 25

x = 5 i - 9, x = - 5 i - 9

Solution steps

(x + 9)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = - 25 : x = 5 i - 9

Solve

x + 9 = - - 25 : x = - 5 i - 9

The solutions to the quadratic equation are:

x = 5 i - 9, x = - 5 i - 9

\frac{9}{4} + 2

(\frac{36}{( 4 + 5 )}) - 1 (2 \cdot 3) (\frac{12}{( 3 + 1 )}) = - 8

\frac{1}{3 + 6} + \frac{2}{6}

- 3 x \leq 24

(6 x)^{\frac{3}{7}}

What are the solutions to the equation (x+9)^2=-25 ?
The solutions to the equation (x+9)^2=-25 are x=5i-9,x=-5i-9
Find the zeros of (x+9)^2=-25
The zeros of (x+9)^2=-25 are x=5i-9,x=-5i-9