What is \sqrt[k]{(1/2+1/(2k))}^k ?

The solution to \sqrt[k]{(1/2+1/(2k))}^k is 1/(2k)+1/2

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simplify \sqrt[k]{(1/2+1/(2k))}^k

simplify

\frac{1}{2 k} + \frac{1}{2}

Solution steps

Apply radical rule:

= (((\frac{1}{2} + \frac{1}{2 k}))^{\frac{1}{k}})^{k}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= ((\frac{1}{2} + \frac{1}{2 k}))^{\frac{1}{k} k}

\frac{1}{k} k = 1

= ((\frac{1}{2} + \frac{1}{2 k}))

Remove parentheses:

(a) = a

= \frac{1}{2} + \frac{1}{2 k}

(1.6 \cdot 1 0^{- 19}) (1.15)

e^{- α z} d z

\frac{100 ( s + 2 )}{s ( s ^{2} + 4 ) ( s + 1 )} e^{- 3}

e^{- 10} \cdot 1 0^{7} \frac{1}{7 !}

120 \cdot 4^{- 0.51457}

What is \sqrt[k]{(1/2+1/(2k))}^k ?
The solution to \sqrt[k]{(1/2+1/(2k))}^k is 1/(2k)+1/2