What is (2/7)^7e(2/7)^{-5} ?

The solution to (2/7)^7e(2/7)^{-5} is (4e)/(49)

Popular >

simplify (2/7)^7e(2/7)^{-5}

simplify

(\frac{2}{7})^{7} e (\frac{2}{7})^{- 5}

\frac{4 e}{49}

Decimal Notation

0.22190 \dots

Solution steps

(\frac{2}{7})^{7} e (\frac{2}{7})^{- 5}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(\frac{2}{7})^{7} (\frac{2}{7})^{- 5} = (\frac{2}{7})^{7 - 5}

= e (\frac{2}{7})^{7 - 5}

Subtract the numbers:

7 - 5 = 2

= e (\frac{2}{7})^{2}

(\frac{2}{7})^{2} = \frac{2 ^{2}}{7 ^{2}}

= e \frac{2 ^{2}}{7 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ^{2} e}{7 ^{2}}

2^{2} = 4

= \frac{4 e}{7 ^{2}}

7^{2} = 49

= \frac{4 e}{49}

y \cdot t^{2} + 1

5^{6} (1 + 4 e^{- 2 (2)})^{- 1}

(\frac{δ k ^{- ρ} l ^{p}}{l ^{p}} + \frac{1 - δ}{l ^{p}})^{- \frac{1}{ρ}}