What is t^2e^{-3t}cos(h)(2t) ?

The solution to t^2e^{-3t}cos(h)(2t) is 2e^{-3t}t^3cos(h)

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simplify t^2e^{-3t}cos(h)(2t)

simplify

t^{2} e^{- 3 t} cos (h) (2 t)

2 e^{- 3 t} t^{3} cos (h)

Solution steps

t^{2} e^{- 3 t} cos (h) (2 t)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

t^{2} t = t^{2 + 1}

= e^{- 3 t} cos (h) \cdot 2 t^{2 + 1}

Add the numbers:

2 + 1 = 3

= e^{- 3 t} cos (h) \cdot 2 t^{3}

1 \cdot (\frac{0.1}{4})^{2} + (\frac{0.1}{4})^{2}

- 2 e^{- x} \cdot 2 e^{- x}

3.815038393 \cdot 1 0^{- 5}

25.8 \cdot 1 0^{- 3} \cdot ln (\frac{1 0 ^{21}}{1.6})

100 (30 e^{- 2 (0.5)}) (15 - 15 e^{- 2 (0.5)})

What is t^2e^{-3t}cos(h)(2t) ?
The solution to t^2e^{-3t}cos(h)(2t) is 2e^{-3t}t^3cos(h)