What is (-2.3)(8.31)(298)(log_{10}(6.45)10^{-8}) ?

The solution to (-2.3)(8.31)(298)(log_{10}(6.45)10^{-8}) is -0.00005…log_{10}(645)+0.00011…

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simplify (-2.3)(8.31)(298)(log_{10}(6.45)10^{-8})

simplify

(- 2.3) (8.31) (298) (lo g_{10} (6.45) 1 0^{- 8})

- 0.00005 \dots lo g_{10} (645) + 0.00011 \dots

Decimal Notation

- 0.00004 \dots

Solution steps

(- 2.3) (8.31) (298) (lo g_{10} (6.45) \cdot 1 0^{- 8})

(- 2.3) (8.31) (298) (lo g_{10} (6.45) \cdot 1 0^{- 8}) = - 2.3 \cdot 8.31 \cdot 298 (lo g_{10} (6.45) \cdot 1 0^{- 8})

= - 2.3 \cdot 8.31 \cdot 298 lo g_{10} (6.45) \cdot 1 0^{- 8}

lo g_{10} (6.45) = lo g_{10} (645) - 2

= - 2.3 \cdot 8.31 \cdot 298 (lo g_{10} (645) - 2) \cdot 1 0^{- 8}

- 2.3 \cdot 8.31 \cdot 298 (lo g_{10} (645) - 2) \cdot 1 0^{- 8} = - 0.00005 \dots lo g_{10} (645) + 0.00011 \dots

= - 0.00005 \dots lo g_{10} (645) + 0.00011 \dots

(5.25 \cdot 1 0^{- 8}) (7.96 \cdot 1 0^{3})

8.2 \cdot 1 0^{- 6} \cdot (202.6 \cdot 1 0^{3} - 101.3 \cdot 1 0^{3})

17 \cdot 0.368 Z^{- 1}

0.045 \cdot 1 0^{- 3}

1 e^{(- 0.03 \cdot 1)}

What is (-2.3)(8.31)(298)(log_{10}(6.45)10^{-8}) ?
The solution to (-2.3)(8.31)(298)(log_{10}(6.45)10^{-8}) is -0.00005…log_{10}(645)+0.00011…