What is the answer to solvefor y,2x-y+5^{x-1}=7*5 ?

The answer to solvefor y,2x-y+5^{x-1}=7*5 is y=-35+2x+5^{x-1}

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solvefor y,2x-y+5^{x-1}=7*5

solve for

y, 2 x - y + 5^{x - 1} = 7 \cdot 5

y = - 35 + 2 x + 5^{x - 1}

Solution steps

2 x - y + 5^{x - 1} = 7 \cdot 5

Multiply the numbers:

7 \cdot 5 = 35

2 x - y + 5^{x - 1} = 35

Move

2 x

to the right side

- y + 5^{x - 1} = 35 - 2 x

Move

5^{x - 1}

to the right side

- y = 35 - 2 x - 5^{x - 1}

Divide both sides by

- 1

y = - 35 + 2 x + 5^{x - 1}

16 - 4

4 x + 2 = \frac{1}{2} x + 17

7 3^{2}

9 (x + 1)^{2} = 16

u^{2} - 3 u - 4 = 0

What is the answer to solvefor y,2x-y+5^{x-1}=7*5 ?
The answer to solvefor y,2x-y+5^{x-1}=7*5 is y=-35+2x+5^{x-1}